3136(t)=-16t^2+3136

Solution for 3136(t)=-16t^2+3136 equation:

3136(t)=-16t^2+3136

We move all terms to the left:

3136(t)-(-16t^2+3136)=0

We get rid of parentheses

16t^2+3136t-3136=0

a = 16; b = 3136; c = -3136;
Δ = b2-4ac
Δ = 31362-4·16·(-3136)
Δ = 10035200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10035200}=\sqrt{5017600*2}=\sqrt{5017600}*\sqrt{2}=2240\sqrt{2}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3136)-2240\sqrt{2}}{2*16}=\frac{-3136-2240\sqrt{2}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3136)+2240\sqrt{2}}{2*16}=\frac{-3136+2240\sqrt{2}}{32}
$